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https://github.com/eclipse-threadx/threadx.git
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Reverted the Linux port mutex retry on this branch
The backport fixes a real deadlock and is right in itself, but on this branch it
reproducibly breaks the NetX Duo nx_secure suite: nx_secure_tls_coverage_test
segfaults in 8 of 19 configurations on one run and 9 of 19 on a re-run of the same
commit, against four consecutive runs with none before it.
Whether the retry causes that or merely exposes something latent is not known. The
first guess, a kernel object outliving its stack frame, is wrong: that test's
sessions are file scope and its creates and deletes balance. The deadlock the
retry cures costs one configuration's coverage data at roughly 0.4% of test
instances, which the union absorbs, so the branch is measurably worse with it than
without while the interaction is unexplained.
This is a deferral, not a dismissal. The diagnosis stands, the reproduction is
recorded, and re-applying is one cherry-pick. The upstream fix is unaffected.
This reverts commit ac95c32c.
Assisted-by: Claude Code (Opus 5) <noreply@anthropic.com>
This commit is contained in:
@@ -525,7 +525,7 @@ VOID _tx_thread_interrupt_restore(UINT previous_posture);
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#define TX_RESTORE _tx_linux_debug_entry_insert("RESTORE", __FILE__, __LINE__); \
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_tx_thread_interrupt_restore(tx_saved_posture);
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#endif /* TX_LINUX_DEBUG_ENABLE */
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#define tx_linux_mutex_lock(p) _tx_linux_mutex_lock_retry(&p)
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#define tx_linux_mutex_lock(p) pthread_mutex_lock(&p)
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#define tx_linux_mutex_unlock(p) pthread_mutex_unlock(&p)
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#define tx_linux_mutex_recursive_unlock(p) {\
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int _recursive_count = (int)tx_linux_mutex_recursive_count;\
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@@ -566,17 +566,6 @@ extern CHAR _tx_version_id[];
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/* Define externals for the Linux port of ThreadX. */
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extern pthread_mutex_t _tx_linux_mutex;
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/* Define how long a thread waits on the Linux mutex before retrying. A thread
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parked on the mutex can be suspended by the port's signal handler and so never
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act on the wake-up the next unlock sends it, which leaves the wake-up lost and
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every other waiter parked on a mutex that is free. */
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#ifndef TX_LINUX_MUTEX_RETRY_NSEC
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#define TX_LINUX_MUTEX_RETRY_NSEC 1000000
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#endif
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void _tx_linux_mutex_lock_retry(pthread_mutex_t *mutex);
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extern sem_t _tx_linux_semaphore;
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extern sem_t _tx_linux_semaphore_no_idle;
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extern ULONG _tx_linux_global_int_disabled_flag;
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@@ -8,8 +8,6 @@
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* SPDX-License-Identifier: MIT
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**************************************************************************/
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// Portions of this file were generated with AI assistance.
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/**************************************************************************/
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/**************************************************************************/
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@@ -208,49 +206,6 @@ struct timespec ts;
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}
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}
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/* Define the ThreadX Linux mutex lock function. The wait is timed and retried
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rather than left to pthread_mutex_lock, because a thread can be signalled into
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the port's suspend handler while it is parked on this mutex. That handler does
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not return until the thread is resumed, so the wake-up the next unlock sends is
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delivered to a thread that never retries and is lost. Any other thread parked
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on the mutex then waits on a mutex that is free. Retrying on a timeout costs
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nothing when the mutex is handed over normally, and turns that lost wake-up into
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a delay of at most the retry period. */
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void _tx_linux_mutex_lock_retry(pthread_mutex_t *mutex)
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{
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INT linux_status;
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struct timespec ts;
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do
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{
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/* Set the deadline for this attempt. */
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clock_gettime(CLOCK_REALTIME, &ts);
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ts.tv_nsec = ts.tv_nsec + TX_LINUX_MUTEX_RETRY_NSEC;
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if (ts.tv_nsec >= 1000000000)
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{
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ts.tv_nsec = ts.tv_nsec - 1000000000;
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ts.tv_sec++;
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}
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linux_status = pthread_mutex_timedlock(mutex, &ts);
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/* Anything but the deadline expiring is a real failure to obtain the
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mutex, so stop retrying. */
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if ((linux_status != 0) && (linux_status != ETIMEDOUT))
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{
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break;
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}
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} while (linux_status != 0);
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}
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void _tx_thread_delete_port_completion(TX_THREAD *thread_ptr, UINT tx_saved_posture)
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{
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INT linux_status;
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